(-1/480)(x^2)+3x=-4

Solution for (-1/480)(x^2)+3x=-4 equation:

(-1/480)(x^2)+3x=-4

We move all terms to the left:

(-1/480)(x^2)+3x-(-4)=0


Domain of the equation: 480)x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x+(-1/480)x^2+4=0

We multiply all the terms by the denominator


3x*480)x^2+(+4*480)x^2-1=0

We add all the numbers together, and all the variables

3x*480)x^2+1920x^2-1=0

Wy multiply elements

1440x^2=0

a = 1440; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1440·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2880}=0$